Inside the square ABCD there is a square DEFG so that [ABP]=[CGFP]+[AFE].
Proof and drawing, attached.
Inside the square ABCD there is a square DEFG so that [ABP]=[CGFP]+[AFE].
Proof and drawing, attached.
Note: I came up with the following proof 53 years ago, during an exam; as the majority of solvers used the 3 concurrent circumcircles of th...