Hi, thanks a lot for the solution. I just have one doubt though.
Can you please look into the part where you claimed that AP is the perpendicular bisector of angle BQ. I know triangle BAQ is isosceles and angle B is equal to angle Q, but can't say that AP bisects the triangle.
Even if you substitute the value of x = 22.5 degrees you will find that AB and BQ are not perpendicular to each other.
Hi, thanks a lot for the solution.
RăspundețiȘtergereI just have one doubt though.
Can you please look into the part where you claimed that AP is the perpendicular bisector of angle BQ. I know triangle BAQ is isosceles and angle B is equal to angle Q, but can't say that AP bisects the triangle.
Even if you substitute the value of x = 22.5 degrees you will find that AB and BQ are not perpendicular to each other.
Please let me know your thoughts about the same.
correction
RăspundețiȘtergere*if you substitute x = 22.5 degrees, you will find that AP and BQ are not perpendicular to each other.
I did not say AP is perpendicular bisector, but A lays onto the perpendicular bisector, this is a huge difference!!
RăspundețiȘtergereSorry about that. How do you reach the conclusion that ABPQ is cyclic?
RăspundețiȘtergereHey I got it!
RăspundețiȘtergereYou are awesome
Thankyou so much